# compareTo method

- num other

override

Compares this to `other`

.

Returns a negative number if `this`

is less than `other`

, zero if they are
equal, and a positive number if `this`

is greater than `other`

.

The ordering represented by this method is a total ordering of num values. All distinct doubles are non-equal, as are all distinct integers, but integers are equal to doubles if they have the same numerical value.

For doubles, the `compareTo`

operation is different from the partial
ordering given by operator==, operator< and operator>. For example,
IEEE doubles impose that `0.0 == -0.0`

and all comparison operations on
NaN return false.

This function imposes a complete ordering for doubles. When using
`compareTo`

the following properties hold:

- All NaN values are considered equal, and greater than any numeric value.
- -0.0 is less than 0.0 (and the integer 0), but greater than any non-zero negative value.
- Negative infinity is less than all other values and positive infinity is greater than all non-NaN values.
- All other values are compared using their numeric value.

Examples:

```
print(1.compareTo(2)); // => -1
print(2.compareTo(1)); // => 1
print(1.compareTo(1)); // => 0
// The following comparisons yield different results than the
// corresponding comparison operators.
print((-0.0).compareTo(0.0)); // => -1
print(double.nan.compareTo(double.nan)); // => 0
print(double.infinity.compareTo(double.nan)); // => -1
// -0.0, and NaN comparison operators have rules imposed by the IEEE
// standard.
print(-0.0 == 0.0); // => true
print(double.nan == double.nan); // => false
print(double.infinity < double.nan); // => false
print(double.nan < double.infinity); // => false
print(double.nan == double.infinity); // => false
```

## Implementation

`int compareTo(num other);`